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Usimov [2.4K]
2 years ago
13

Tell me if I’m correct

Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0

Answer:

Yah i think i remember doing this question once, it looks correct, i hope you do well on the test

Have a nice day!! :)

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Step-by-step explanation:

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Which expression best estimates 6 and three-fourths divided by 1 and two-thirds?
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A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e
ladessa [460]

Answer:

\frac{r(1-\sqrt{2})}{-3}

Step-by-step explanation:

Volume of cone = \frac{1}{3} \pi r^{2} h

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

                          = \frac{1}{3} \pi r^{2} \times r

                          = \frac{1}{3} \pi r^{3}

Surface area of cone including 1 base = \pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}

Since r = h

So, area = \pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}

              = \pi r^{2} +\pi\times r \times \sqrt{2r^2}

              = \pi r^{2} +\pi\times r^2 \times \sqrt{2}

Ratio of volume of cone to its surface area including base :

\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}

\frac{\frac{1}{3}r}{1+\sqrt{2}}

\frac{r}{3(1+\sqrt{2})}

Rationalizing

\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}

\frac{r(1-\sqrt{2})}{-3}

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is \frac{r(1-\sqrt{2})}{-3}

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3 years ago
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I need help with this ^
Nady [450]
<h3>Answer is 20 </h3>

<h2>Please mark me as Brainliest ......</h2>

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Which shows 4x+2y=-16
mrs_skeptik [129]
4x+2y=-16
answer is -2,-8
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