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2 years ago

Tell me if I’m correct

Mathematics

1 answer:

VLD [36.1K]2 years ago

7 0

Answer:

Yah i think i remember doing this question once, it looks correct, i hope you do well on the test

Have a nice day!! :)

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What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15?

Dafna1 [17]

Step 1

Find the slope of the given line

we have

$3x+4y=15$

Isolate the variable y

Subtract $3x$ both sides

$3x+4y-3x=15-3x$

$4y=-3x+15$

Divide by $4$ both sides

$y=-\frac{3}{4}x+ \frac{15}{4}$

the slope of the given line is

$m=-\frac{3}{4}$

Step 2

Find the equation of the line that passes through the point $(8,-2)$ and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to

$y-y1=m(x-x1)$

we have

$m=-\frac{3}{4}$

$(x1,y1)=(8,-2)$

substitute in the equation

$y+2=-\frac{3}{4}(x-8)$

$y=-\frac{3}{4}x+6-2$

$y=-\frac{3}{4}x+4$ or $3x+4y=16$

therefore

the answer is

$y=-\frac{3}{4}x+4$

$3x+4y=16$

8 0

2 years ago

The given line passes through the points (0, ) and (2, 3). On a coordinate plane, a line goes through (0, negative 3) and (2, 3)

Kipish [7]

Answer:

$y=\frac{x}{5}+\frac{12}{5}$

Step-by-step explanation:

1) The Point-slope form equation is given in this form:

$(x-x_{0})=m(y-y_{0})$

2)Looking at the given graph, we can pick two points: (-5,-4) and (0,-3)

3) Before using the Point-slope form We have to find out the slope:

$m=\frac{-4-(-3)}{0-(-5)} \Rightarrow m=\frac{-4+3}{0+5} \Rightarrow m=\frac{-1}{5}$

4)Parallel lines share the same slope. The one that passes through (-2,2) is found by calculating its linear parameter "b":

$y=\frac{x}{5}+b\Rightarrow 2=\frac{-2}{5}+b\\5*10=(-2+b)*5\Rightarrow 5b=12 \Rightarrow \frac{5b}{5} =\frac{12}{5} \Rightarrow b=\frac{12}{5}$

Then, the answer is:

$y=\frac{x}{5}+\frac{12}{5}$

5 0

2 years ago

Read 2 more answers

Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0

3 years ago

Which voting methods satisfy the Majority Fairness Criterion?

leonid [27]

It is a single-winner voting system criterion used to compare such systems.

3 0

3 years ago

A text book cost 65.49$ before tax. the tax on the textbook is 6.5%.what is the total cost of the textbook.

trapecia [35]

6.5% tax on $65.49=0.065×65.49=$4.26 To the nearest cent, so add this to 65.49=$69.75.

6 0

3 years ago