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Liono4ka [1.6K]

3 years ago

6

Em um jogo de futebol, atletas masculinos percorrem em média 11Km, sendo que a distância percorrida ao longo do primeiro tempo é

superior em 5% com relação ao segundo tempo (EKBLOM, 1986; RIENZI et al., 2000). Levando em consideração que um time de futebol tem 10 jogadores de linha e todos eles percorrem a mesma distância e não são substituídos, qual a distância média total que um time pode percorrer em uma partida? *

1 answer:

ohaa [14]3 years ago

8 0

Answer:225.5 km

Step-by-step explanation:

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tapes-r-us is have a sale on hq tape players. The regular price is $60. The discount is $18. What percent discount is this?

olga nikolaevna [1]

The discount is 30%

Step-by-step explanation:

Given

Price of tape = $60

Discount = $18

In order to find the percentage, we will use the percentage formula

$Percentage = \frac{discount}{Price}*100\\= \frac{18}{60} *100\\=0.3 * 100\\= 30\%$

Hence,

The discount is 30%

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A new truck that sells for $29,000 depreciates 12% each year. Which function models the value of the truck?

ladessa [460]

V = 29,000/(1.12)^years

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3 years ago

12 in. to 1 ft. Reduce, Enlarges, or Preserved the size

Leviafan [203]

Preserved the size because 12inchs is = to 1 ft.

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3 years ago

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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2$

$n = 2401$

The minimum sample size is 2401.

4 0

3 years ago

What’s the answer to this!!!

aliina [53]

Answer:

8.54

Step-by-step explanation:

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3 years ago

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