when adding or subtracting outside parentheses or absolute value bars , what is the transformation of the function
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Answer:
There is one extraneous solution at
The only solution is
Step-by-step explanation:
Given:
The equation to solve is given as:
In order to solve, we will first isolate the radical part.
<em>Adding -5 on both the sides, we get:</em>
<em>Now, squaring both the sides, we get:</em>
Now, let us check whether the calculated values satisfy the equations or not.
Plug in 4 and 7 for 'x' and check the value of the equation.
At ,
But, 6 is not equal to 4 and hence 4 is not a solution to the given equation. It is an extraneous solution for the given equation.
Now, at
Therefore, is a solution to the equation.
Hence, there is one extraneous solution at
The only solution is