Answer:
EY = 60
DW = 68
DE = 128
Step-by-step explanation:
Given
As YW is the perpendicular bisector of EF, then EY = FY
FY = √(FW² - YW²) = √(68² - 32²) = 60
⇒ EY = 60
As WX is the perpendicular bisector of DF, then DW = FW
As FW = 68, then DW = 68
As WZ is the perpendicular bisector of DE, then DZ = EZ = 64
Therefore, DE = DZ + EZ = 64 + 64 = 128
Answer:
20
Step-by-step explanation:
The expected value of a toss is:
E(X) = (0.10) (3) + (0.30) (1) + (0.60) (0)
E(X) = 0.6
If she scores an average of 0.6 points per toss, then the expected number of tosses needed to get 12 points is:
12 / 0.6 = 20
Using a random number table, we can assign digit 0 as a 3-point hole, digits 1-3 as a 1-point hole, and digits 4-9 as no points. Read the digits and add the points until you get 12 points. The number of digits read is the number of beanbag tosses.
For number 7:
a) The sum of the adjacent angles is 180. Because if its any three angles thats half of the angles all together 3/6 = 180/360.
b) The sum of the angles in the center is 360 degrees. Because 60 x 6 = 360.
c) The unknown angles (center angles) are 61.25 degrees.
For number 8 (bonus):
It's C) 90 Degrees, because it's a right angle.
Hope this helps :)
Answer: $22.80/hour
Step-by-step explanation: 364.80 : 16 = 22.80
