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3 years ago

Which ordered pair is a solution of the equation

1 answer:

4 0

(0,-7)
-7=11(0)+4
-7=0+4
-7 is not 4 -----not a solution

(-1,-7)
-7=11(-1)+4
-7=-11+4
-7=-7 ----solution

(1,-7)
-7=11(1)+4
-7=11+4
-7=15
-7 is not 15 ----not a solution

(2,26)
26=11(2)+4
26=22+4
26=26 ----soltion

(-1, -7) & (2, 26) are solutions to the equation

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The distance between Anubhav’s school and his house is 45 km. He started from his house for school at 7:00 am and covered 30 km

8_murik_8 [283]

Answer:

45 km/h

Step-by-step explanation:

In the first part of the trip, he already covered 30 km so we can subtract that from the total distance

45 - 30 = 15

This means he has 15 km to go

He also took an hour, or 60 minutes, to get to school. We subtract the time spent of the first part and time spent talking to a friend from the 60 minutes

60 - 35 = 25

25 - 5 = 20

He took 20 minutes to cover the second part of the journey

Speed = distance/time

15/20 = 0.75

He covered 0.75 km per MINUTE

to find it in km/h, we just multiply the number by 60

0.75 x 60 = 45

6 0

3 years ago

Read 2 more answers

What is the answer to this question ?

STALIN [3.7K]

A is not commutative with the above expression
your answer is A

4 0

3 years ago

carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position

Volgvan

That'd be a total of 6 km east and 4 km north.

The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.

However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:

sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km

3 0

3 years ago

Read 2 more answers

PLEASE HELP WILL MARK YOU BRAINLIEST !!!!! D; I SWEARR

Setler79 [48]

Whattttttt!!!!!!!!!!!!!!!!!

7 0

3 years ago

Plz help me!!!

Nadya [2.5K]

To solve this we are going to use the exponential function: $f(t)=a(1(+/-)b)^t$
where
$f(t)$ is the final amount after $t$ years
$a$ is the initial amount
$b$ is the decay or grow rate rate in decimal form
$t$ is the time in years

Expression A
$f(t)=624(0.95)^{4t}$
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate $b$ , we are going to use the formula: $b=|1-base|$ *100%
$b=|1-0.95|$ *100%
$b=0.05$ *100%
$b=$ 5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at $t=0$
$f(t)=624(0.95)^{4t}$
$f(0)=624(0.95)^{0t}$
$f(0)=624(0.95)^{0}$
$f(0)=624(1)$
$f(0)=624$
We can conclude that the initial value of expression A is 624.

Expression B
$f(t)=725(1.12)^{3t}$
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
$b=|1-base|$ *100%
$b=|1-1.12|$ *100
$b=|-0.12|$ *100%
$b=0.12$ *100%
$b=$ 12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at $t=0$
$f(t)=725(1.12)^{3t}$
$f(0)=725(1.12)^{0t}$
$f(0)=725(1.12)^{0}$
$f(0)=725(1)$
$f(0)=725$
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0

3 years ago