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padilas [110]
3 years ago
15

A midsegment of a triangle measures 14.7 feet. What is the length of the corresponding base of the triangle?

Mathematics
2 answers:
kaheart [24]3 years ago
7 0

The correct answer is:  [A]:  " 29.4 ft. "

___________________________________________________

Explanation:

___________________________________________________

Solve for "b" ; which is the "base" .

14.7 ft. = (1/2) * b ;

→  (1/2) * b = 14.7 ft ;

Multiply EACH SIDE of the equation by "2" ;

    to isolate "b" on one side of the equation;  & to solve for "b" ;

___________________________________________________

2 * { (1/2) b } = 2 * (14.7 ft) ;

to get:

b = 29.4 ft . ;

_______________________________________________________

          →  which is:  Answer choice:  [A]:  " 29.4 ft. "

________________________________________________________

Reika [66]3 years ago
6 0

Answer:

A.     29.4 ft

Step-by-step explanation:

I hioe this helps!!!

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An art history professor assigns letter grades on a test according to the following scheme. A: Top 13%13% of scores B: Scores be
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Answer:

The numerical limits for a B grade is between 81 and 89.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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\mu = 79.7, \sigma = 8.4

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Below the top 13%:

Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So

Z = \frac{X - \mu}{\sigma}

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X - 79.7 = 8.4*1.127

X = 89

Above the bottom 56:

Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 8.4*0.15

X = 81

The numerical limits for a B grade is between 81 and 89.

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3 years ago
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