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Sergio039 [100]
3 years ago
7

Vince’s Vans table is shown. Complete the process column in the table, then create a verbal description and an algebraic rule to

represent the cost of renting from Vince’s Vans. Use these representations, along with the graph for Vince’s Vans that you created in question 4, to answer questions 6 and 7.
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer:

kay

Step-by-step explanation:

You might be interested in
Wright the ratio 4.5 : 2.35 in the form n : 1
sergeinik [125]

Answer:

\frac{9}{47}: 1

Step-by-step explanation:

you can divide both sides by 2.35 to get the right side to be 1:

4.5: 2.35\\\frac{9}{47}: 1

6 0
2 years ago
Determine whether the number is rational or irrational and round it to the nearest hundredth. - 3/7​
ivann1987 [24]

Answer:

Yes, it's a rational number

Step-by-step explanation:

-3/7. It is a rational because. It can be written as p/q form. Where p/q are non zero number. And in decimal it would be -0.42

6 0
3 years ago
Read 2 more answers
Let f be the function given by f(x) = x+4(x−1)(x+3) on the closed interval [−5,5]. On which closed interval is the function f gu
Vlad [161]

Answer:

Step-by-step explanation:

f(x)=x+4(x^2+2x-3)=4x^2+9x-12

f'(x)=8x+9

f'(x)=0,gives x=-9/8

f(-5)=-5+4(-5-1)(-5+3)=-5+4*-6*-2=43

f(-9/8)=-9/8+4(-9/8-1)(-9/8+3)

=-9/8+4*-17/8*15/8

=-9/8-255/16

=-273/16=-17 1/16

f(5)=4*5^2+9*5-12=100+45-12=133

absolute maximum=133

absolute minimum=-17 1/16

6 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
2 years ago
Alyssa is paid a 5 percent commission on her total sales each month. Last month, she sold $30,000 worth of items. After a state
grigory [225]
$1,365 is the answer, (the third choice)
3 0
3 years ago
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