By taking a common factor, we will see that the equivalent expression is:
![12*\sqrt[3]{6c}](https://tex.z-dn.net/?f=12%2A%5Csqrt%5B3%5D%7B6c%7D)
<h3>
How to find the equivalent expression?</h3>
Here we start with the expression:
![5*\sqrt[3]{6c} + 7*\sqrt[3]{6c}](https://tex.z-dn.net/?f=5%2A%5Csqrt%5B3%5D%7B6c%7D%20%2B%207%2A%5Csqrt%5B3%5D%7B6c%7D)
Notice that if we define:
![\sqrt[3]{6c} = u](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B6c%7D%20%3D%20u)
We can rewrite our expression as:

Now we can take the common factor u to write:

Now if we replace u y the cubic root, we will get:
![12*\sqrt[3]{6c}](https://tex.z-dn.net/?f=12%2A%5Csqrt%5B3%5D%7B6c%7D)
So the correct option is the third one.
If you want to learn more about expressions:
brainly.com/question/2972832
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Answer:
see below
Step-by-step explanation:
To graph this equation, start at the origin (0,0) since there is not y-intercept.
Because slope is characterized by rise/run ( i.e. how many units up or down depending on whether it is positive or negative and then however many units to the right.
Because the rise (up and down, numerator) is 1, we know that we will go up one unit.
The run (side to side, denominator) is 4, so we will go to the right 4 units.
This makes the first point (4, 1).
Continue doing this until you get an idea of the line and connect the points to get the graph
A) 2m+4=5 , is the result of cross multiplying
Answer:
2.5, -1.25, 0.625
Step-by-step explanation:
A parabola graph is a graph where the line is curved. A linear graph is a graph where the line is straight.