615 - 6 = 609
963 - 6 = 957
609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.
It'd be 54. Its flipping the numbers, adding two, flipping again, repeat.
Answer:

Step-by-step explanation:

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Answer:
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Step-by-step explanation:
If the line goes straight it has no slope
In this case you equation should be just
X=2