(2/3)=0.66667=x/y
x+y=60
x=60-y
(60/y)-1=2/3
60/y=5/3
y=36
x+36=60
x=24
24:36
Answer:option B & D are correct
Step-by-step explanation:
Given options are
A B C D E
Tether ball pole shadow 1.35 1.8 3.75 0.6 2
Flagpole shadow 3.4 4.08 8.35 1.36 4.8
Ratio of corresponding height & shadows should be same
3 meter tall tether ball pole and a 6.8 tall flagpole
=> Ratio = 6.8/3 = 68/30 = 34/15
A - 3.4/1.35 = 340/135 ≠ 34/15( 306/135)
B - 4.08/1.8 = 408/180 = 34/15 = 34/15 ( Correct option)
C 8.35/3.75 = 835/375 = 167/75 ≠ 34/15( 170/75)
D 1.36/0.6 = 136/60 = 34/15 = 34/15 ( Correct option)
E 4.8/2 = 48/20 = 12/5 = 36/15 ≠ 34/15
option B & D are correct
The easist way i can think of doing this would be to multipy the 22.5 miles by three so you can see how far he would go if he had one hour to travel at that average speed, the answer after multipying by 3 is 67.5 miles per hour, which in most plavces he would b considered speeding.
A (2, -3/2) baisicly it is is a line and it is vertical so this one is more easy.
27 = 9^x-1
3^3 = 9^x-1
3^3 = 3^2(x-1)
3 = 2 (x-1)
1.5 = x-1
x = 2.5
