The minimum legth of a codon could be two. If it was only one of the 6 nitrogeneous bases in a codon, we'd only have 6 possible amino acids. If we have, though, a combination of two amino acids out of the 6 nitrogeneous bases, we would have then 36 possible combinations (6 possibilities for the first position × 6 possibilities for the second position) that would allow the existence of the 20 different amino acids.
In the human case, for example, with only 4 nitrogeneous bases, a combination of two amino acids would be insufficient (4×4=16) for the 20 amino acids.
They are found in the body
Answer:
2.94 × 10²⁰ N/C
Explanation:
Given that:
The nucleus of "Lead-208 has 82 protons,
with a radius (r) 6.34×10-15 m, &
each electric charge has a value of 1.60218 × 10^-19 C
∴ The formula for calculating an electrical field at the surface of the nucleus is:
Substituting our values into the equation above, we have;
E = 
E = 2.93870499×10²⁰ N/C
E ≅ 2.94 × 10²⁰ N/C
Answer:
A) tortoiseshell female; black male
Explanation:
Females have two X chromosomes and males have an X and a Y chromosome.
<u>The possible genotypes and phenotypes are</u>:
- XᵒXᵒ: black female
- XᵒY: black male
- XᴼXᴼ: orange female
- XᴼY: orange male
- XᵒXᴼ: tortoiseshell female
<u>Cross of a black female and an orange male</u>
<h3>XᵒXᵒ x XᴼY</h3>
The female only produces Xᵒ gametes. The male produces Xᴼ and Y.
The possible offspring therefore is: XᵒXᴼ (tortoiseshell females) and XᵒY (black males). The answer is A.
Genetic variation occurs.
Mutations are not copied over and over again.
