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Andreas93 [3]
3 years ago
10

What is the equation of the line that is parallel to the line whose equation is y=-4/3x+7/3 and also passes through the point (-

5,2)
Mathematics
2 answers:
Artemon [7]3 years ago
8 0

Answer: please help me with this, I will do whatever you want but please help me please!

Step-by-step explanation:

Bumek [7]3 years ago
8 0

Answer:

y=-\frac{4}{3} x-\frac{14}{3}

Step-by-step explanation:

Linear equations are typically organized in slope-intercept form:

y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Determine the slope (m)</u>

Parallel lines will always have the same slope. Therefore, this line will have the same slope as the given line y=-\frac{4}{3} x+ \frac{7}{3}.

Plug in -\frac{4}{3} as the slope

y=-\frac{4}{3} x+b

<u>2) Determine the y-intercept (b)</u>

To find the y-intercept, plug the given point (-5,2) into the equation and solve for b.

2=-\frac{4}{3}(-5)+b\\2=\frac{20}{3}+b

Subtract both sides by \frac{20}{3}

2-\frac{20}{3} = \frac{20}{3}+b-\frac{20}{3}\\\frac{6}{3} -\frac{20}{3}=b\\-\frac{14}{3} = b

Therefore, the y-intercept is -\frac{14}{3}.

<u>3) Plug the y-intercept back into our original equation</u>

y=-\frac{4}{3} x-\frac{14}{3}

I hope this helps!

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