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Bingel [31]
2 years ago
14

Estimate 11.14+9.543 by first rounding each number to the nearest tenth. HELP PLSZZ

Mathematics
1 answer:
True [87]2 years ago
6 0

To round each number to the nearest tenth, we have to look at the second digit after the decimal point, the hundredths. We look at tenths to round whole numbers, hundredths to round tenths, thousandths to round hundredths, etc. If the digit is 4 or below, then we would round down. If the digit is 5 or up, we would round up.

11.14

The digit is below 5, so we round down to 11.1.

9.543

The digit is also below 5, so we round down to 9.5.

Henceforth, adding these two numbers, we can conclude that an accurate estimation of the sum is 11.1 + 9.5, or 20.6.

If we wanted to round this answer further, we would use the same rounding rule. 20.6, where the tenths place digit, 6, is above 5, would be rounded up to 21.

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Step-by-step explanation:

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2 years ago
(Please help!!) Arnold is paid a graduated commission on sales. He earns 7% on sales up to $10,000 and 10% on sales over that am
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Answer:

Step-by-step explanation:

10000*7%= $700.00

2500-700=1800

1800 is 10% of 18,000

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4 0
2 years ago
Aida applied the distributive property to write the equivalent expressions below.
morpeh [17]

Answer:

The answer is b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Determine the value of x in the figure.
telo118 [61]
Your answer is in the picture.

6 0
3 years ago
Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi
natta225 [31]

Answer:

b. circle; 2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0

Step-by-step explanation:

The given conic has equation;

x^2-5x+y^2=3

We complete the square to obtain;

(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}

This is a circle with center;

(\frac{5}{2},0)

This implies that;

x=\frac{5}{2},y=0

When the circle is rotated through an angle of \theta=\frac{\pi}{3},

The new center is obtained using;

x'=x\cos(\theta)+y\sin(\theta) and y'=-x\sin(\theta)+y\cos(\theta)

We plug in the given angle with x and y values to get;

x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3}) and y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})

This gives us;

x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}

The equation of the rotated circle is;

(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}

Expand;

(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}

Multiply through by 4; to get

4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37

Write in general form;

4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0

Divide through by 2.

2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0

8 0
3 years ago
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