Answer:
By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Average of 1,200 dollars and a standard deviation of 900 dollars.
This means that 
Sample of 10.
This means that 
The sampling distribution of the sample mean amount of money in a savings account is
By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
Answer:
$58.25
Step-by-step explanation:
142.20 - 24.50 = 117.50
117.50 / 2 = 58.25
Answer:
3.2
Step-by-step explanation:
For this we need to get the entire volume of the mixture. We get it by summing each quantities:
Vol = 10.6 + 0.6 + 8 = 19.2 L
So, we have 19.2 L for 6 bowls.
For getting the punch of each bowl we just need to divide this volume between the 6 bowls:
19.2 / 6 = 3.2 L
So, each bowl has 3.2 L
Answer:
The desired divisor is n = 21
Step-by-step explanation:
Let that number be n. Then:
-15/56 -5
---------- = ---------
n 6
Through cross-multiplication we get:
(-15/56)*6 = -5n, which reduces to:
(-15)(7) = -5n, or 3(7) = n
The desired divisor is n = 21
