Do you still need the answer? if so i believe the answer is the third one
hope this helps and have a wonderful day :)
Answer:
CI = (70.861 , 94.418)
Step-by-step explanation:
In order to determine the 90% confidence interval you use the following formula (for a population approximately normal):
(1)
: mean = 82.64
σ: standard deviation = 14.32
n: sample = 4
α: tail area = 1 - 0.9 = 0.1
Z_α/2 = Z_0.05: Z factor = 1.645
You replace these values and you obtain:

The confidence interval will be:

The 90% confidence interval is (70.861 , 94.418)
Answer:
The slope of line p is 3 and the slope of line q is -3.
5.2 x 10-2 and 5.2 x 10-1
To find the number of days, divide the total swam by the average:
Days = 48 / 3.2 = 15
They swam for 15 days.