All categories

3 years ago

Associative property 8×30

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

Answer:

I think you mean commutative property. 30 * 8

Step-by-step explanation:

This does not have parentheses around anything. To solve with commutative property switch the digits.

You might be interested in

A store sells comic books. Each comic book costs the same amount. During a sale, the store reduces the price of each comic book

Kruka [31]

Answer:

the original price is $7.89

the price on sale is $6.44

i hope this helps

Step-by-step explanation:

divide $12.88 by 2 to get the price of one of those comic books on sale which gives you $6.44

if you want the original price you just add $1.45 to $6.44 and then thats the price before the sale.

8 0

3 years ago

What is the fraction ten fourteenths in it simplest form?

nadya68 [22]

10/14 = 5/7.

5/7 is your answer. Divide both the numerator and the denominator by a number that they both have in common - 2.

3 0

3 years ago

Read 2 more answers

Need help with all 3

m_a_m_a [10]

Answer:

Theres a website that can help

Step-by-step explanation:

4 0

3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

4 years ago

5÷x-4 - 2÷x+2 = 4÷x-4

Alborosie

I'd suggest you begin by subtracting 4 / (x-4) from both sides. Doing that would leave you with 1 / (x-4) - 2 / (x+2) = 0.

LCD is (x-4)(x+2). Mult. all three terms by (x-4)(x+2). The resulting equation is

x+2 - 2(x-4) = 0. Then x+2 = 2x - 8 => x = 10

Subst. 10 for x in the original equation to verify that 10 is indeed a solution.

8 0

3 years ago

Associative property 8×30​

Associative property 8×30