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Fofino [41]
3 years ago
3

PLEASE HELP THIS HAS A TIMER The following two-way table shows the distribution of daily traffic and weather issues in a certain

large city.
A 4-column table with 3 rows. Column 1 has entries bad weather, good weather, total. Column 2 is labeled heavy traffic with entries 25, 55, 80. Column 3 is labeled Light traffic with entries 5, 15, 20. Column 4 is labeled Total with entries 30, 75, 100. The columns are titled daily traffic and the rows are titled weather conditions.

Suppose a day from this city is selected at random. Let event A = heavy traffic and event B = bad weather. Are events A and B independent?

No, P(A) = P(B|A).
No, P(A) ≠ P(A|B).
Yes, P(A) = P(A|B).
Yes, P(A) ≠ P(B|A).

Mathematics
2 answers:
Len [333]3 years ago
7 0

Answer:

I believe the answer is (B).

Both are not independent, and the probability of A is 30/100.

While the probability for A|B is like 30/100(80/100) which does not equal 30/100.

I've been trying to figure out how to do it and stuff, and this seems the most reasonable answer. I'm taking it now. Goodluck

ED2021

romanna [79]3 years ago
4 0

Answer:

ok im not sure about this but i thank the answer is c

Step-by-step explanation:

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