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hichkok12 [17]
2 years ago
10

Someone please help me, use a variable to represent the situation, and solve the equation using inverse operations.

Mathematics
2 answers:
Scorpion4ik [409]2 years ago
4 0

Answer:

36 in

Step-by-step explanation:

T= toucan

M= macaw

T= 2/3M

T= 24

24= 2/3M

72=2M

36= M

Zinaida [17]2 years ago
3 0

ANSWER:

Let the length of average macaw be x, then length of an average toucan be 2/3x.

So, according to question

2/3x = 24

2x = 72

x = 72/2

x = 36in.

Hence, length of an average macaw is 36in.

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Solve for b A= \frac{a+b}{2}
lina2011 [118]
A = (a+b)/2
2*A = 2*(a+b)/2 ... multiply both sides by 2
2A = a+b
2A-a = a+b-a ... subtract 'a' from both sides to isolate b
2A-a = b
b = 2A-a

Answer: b = 2A-a

6 0
3 years ago
Toby bought 8 hotdogs and 5 fries. It cost $34.00
ruslelena [56]

Answer:

Each hot dog = $3

Each french fry = $2

Step-by-step explanation:

First, lets define our variables:

x = Hotdog

y = fries

Next, you need to set up a cost equation for both Toby and Bernie:

8x + 5y = 34

2x + 6y = 18

Now, we need to isolate one of the variable:

2x + 6y = 18

2x = 18 - 6y

x = 9 - 3y

Next, we need to insert this equation back into the first equation (8x+5y = 34) to find the cost of y (fries):

8x +5y = 34

8 (9-3y) + 5y = 34

72 - 24y + 5y = 34

72 - 19y = 34

19y = 38

y or fries = $2

Finally, we need to find the cost of each hotdog by using the cost of fries ($2) in one of the formulas:

2x + 6y = 18

2x + 6(2) = 18

2x + 12 = 18

2x = 6

x or hotdog = $3

I hope this helps!

-TheBusinessMan

6 0
3 years ago
Please answer I need help to pass
Goryan [66]

Answer:

the answer is A

5 0
3 years ago
Sixty seven percent of the employees in a company have managerial positions, and 58 percent of the employees in the company have
Kazeer [188]

Answer: The proportion of employees who either have MBAs or are managers are 0.58.

Step-by-step explanation:

Since we have given that

Probability of employees having managerial positions = 67%

Probability of employees having MBA degrees = 58%

Probability of managers having MBA degrees = 67%

So, using probability formulas, we get that

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.67+0.58-0.67\\\\P(A\cup B)=0.58

Hence, the proportion of employees who either have MBAs or are managers are 0.58.

7 0
3 years ago
PLEASE HELP, LIMITED TIME!!!!!
Elenna [48]
48 i believe thats the best i can find
3 0
3 years ago
Read 2 more answers
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