simon says that to find the area of a trapezoid, you can multiply the height by the top base and the height by the bottom base.
Then add the two products together and divide the sun by 2. Is Simon correct? Explain your answer.
2 answers:
He is correct
basically you have
h times base1+h times bsae 2 all divided by 2
that equals
(hb1+hb2)/2
if we undistribute h using distributive property which is ab+ac=a(b+c)
(h)(b1+b2)/2
if you split the trapezoid in half with a horizontal line that passes through the halfway point of the height and take those two shapes and put them side by side and cut the triangles off the ends and add them, you will see why this is true
the reason is becuase you can get to the area formula from that is height times (b1+b2)/2
basically you have
h times base1+h times bsae 2 all divided by 2
that equals
(hb1+hb2)/2
if we undistribute h using distributive property which is ab+ac=a(b+c)
(h)(b1+b2)/2
if you split the trapezoid in half with a horizontal line that passes through the halfway point of the height and take those two shapes and put them side by side and cut the triangles off the ends and add them, you will see why this is true
the reason is becuase you can get to the area formula from that is height times (b1+b2)/2
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Answer:
203 feet.
Step-by-step explanation:
Please find the attachment.
Let h represent the height of the building.
We have been given that at 3:30 in the afternoon in mid-September the Kimball Tower casts a shadow about 290 feet long when the sun's rays come down at an angle about 35 degrees above the horizontal.
We know that tangent relates opposite side of a right triangle to its adjacent side.
Upon substituting our given values in above formula, we will get:
Therefore, the building is approximately 203 feet high.
There are 12 project managers that are employed by Mr. Wells
<h3>Further explanation</h3>Solving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
<em>m → gradient of the line</em>
<em>( 0 , c ) → y - intercept</em>
Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :
If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :
<em>Let us tackle the problem!</em>
This problem is about Directly Proportional.
<em>There were 8 engineers under every team leader.</em>
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- Infinite Number of Solutions : brainly.com/question/5450548
- System of Equations : brainly.com/question/1995493
- System of Linear equations : brainly.com/question/3291576
Grade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point
