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marin [14]
3 years ago
12

find the equation of a line that is perpendicular to line g that contains (P,Q) will give brainlest to whoever answers

Mathematics
2 answers:
Fudgin [204]3 years ago
3 0

Answer:

Consider points (-3,6) and (0,5)

gradient \:  \: m =  \frac{(6 - 5)}{( - 3 - 0)}  \\ m =  -  \frac{1}{3}  \\ for \: perpendicular \: gradient \: m {}^{.}  \\ m {}^{.}  \times m =  - 1 \\  -  \frac{1}{3} m {}^{.}  =  - 1 \\ m {}^{.}  = 3 \\ from \: y = mx + c \\ at \:(0,5) \:  \: 5 = 0 \times 3 + c \\ c = 5 \\ hence \: equation \: is \:  \: y = 3x + 5

larisa86 [58]3 years ago
3 0

Step-by-step explanation:

This is your answer. Thanks.

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Select the correct answer from each drop-down menu.
9966 [12]

Answer:

(0.392 ; 0.508)

Step-by-step explanation:

Given that :

p = 45% = 0.45

α = 1 - 90% = 0.1

Zα/2 = Z0.01/2 = Z0.05 = 1.645 (from Z standard table).

Using the relation :

p ± Z0.05*sqrt((p(1-p))/n)

p ± 1.645 * sqrt(0.45(0.55)/200)

p ± 1.645 * sqrt(0.0012375)

p ± 1.645 *0.0351781

0.45 - (1.645 * 0.0351781) = 0.3921320255

0.45 + (1.645 * 0.0351781) = 0.5078679745

(0.392 ; 0.508)

4 0
3 years ago
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jok3333 [9.3K]

Answer:

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7 0
3 years ago
What are the coordinates of the point on the directed line segment from (-9, -1)(−9,−1) to (-9, -10)(−9,−10) that partitions the
mihalych1998 [28]

Answer:

Therefore the co-ordinate of the point on the line segment from (-9,-1) to(-9,-10) into a ratio internally is (-9,-7).

Therefore the co-ordinate of the point on the line segment from (-9,-1) to(-9,-10) into a ratio internally is (-9,-19).

Step-by-step explanation:

Given points are (-9,-1) and (-9,-10)

If a point divides the line segment by joining two points (x₁,y₁) and (x₂,y₂)  into a ratio m:n internally.

Then the point of the coordinate is (\frac{m.x_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}).

If a line segment is externally divided into a point by joining two points (x₁,y₁) and (x₂,y₂) with m: n ratio.

Then the point of the coordinate is (\frac{m.x_2-nx_1}{m-n},\frac{my_2-ny_1}{m-n}).

Internally

The co-ordinate of the point is (\frac{(-9)\times2+(-9)\times 1}{2+1},\frac{(-10)\times 2+(-1)\times 1}{2+1})

                                                 =(-9,-7)

Externally

The co-ordinate of the point is (\frac{(-9)\times2-(-9)\times 1}{2-1},\frac{(-10)\times 2-(-1)\times 1}{2-1})

                                                   =  (-9,-19)

6 0
3 years ago
If R is between A and D and<br> DR = 8 and DA = 15 then AR=
dolphi86 [110]

Answer:

7

Step-by-step explanation:

heres a model

A ----------R---------D

A ----?-----R----8---D

A----------15----------D

15 - 8 = 7

AR = 7

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825 thats the answer
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