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BARSIC [14]
2 years ago
11

. If 3k = 10, what is the value of 6/5 k 2?

Mathematics
2 answers:
Vlad [161]2 years ago
7 0
6k is 20 5k is 15 that’s your answer
Papessa [141]2 years ago
4 0

Answer:

3k=10 so 6k=20 i dont really know the 5k

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A calculator that cost $60 in 1980 now sells for $10. What was the percent of decrease​
Romashka-Z-Leto [24]

Answer: 16.6%

Step-by-step explanation:

$60 divided by 6 = $10

so divide 100 by 6 and you get about 16.6

I Hope this Helps!

4 0
3 years ago
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The population of a city is growing at an average rate of 3% per year in 1990 the population was 45 000.
Nonamiya [84]
This is an exponential growth/decay problem...

F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case:

F=I(1.03)^t  and they just want to know when F=2I so

2=1.03^t  take natural log of both sides...

ln2=t*ln1.03

t=ln2/(ln1.03)

t≈23.45

So it will take approximately 23.45 years for the population to double..

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5 0
3 years ago
A matatu carries 14 passengers per trip. In
PilotLPTM [1.2K]

Answer:

"23,520"

Step-by-step explanation:

one trip: 14 passengers

one day: 3 trips

passengers: 80

80x14= 1,120

1,120x3= 3,360

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6 0
2 years ago
Refer to the Trowbridge Manufacturing example in Problem 2-35. The quality control inspection proce- dure is to select 6 items,
Ivanshal [37]

Answer:

77.64% probability that there will be 0 or 1 defects in a sample of 6.

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The true proportion of defects is 0.15

This means that p = 0.15

Sample of 6:

This means that n = 6

What is the probability that there will be 0 or 1 defects in a sample of 6?

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.15)^{0}.(0.85)^{6} = 0.3771

P(X = 1) = C_{6,1}.(0.15)^{1}.(0.85)^{5} = 0.3993

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3771 + 0.3993 = 0.7764

77.64% probability that there will be 0 or 1 defects in a sample of 6.

5 0
3 years ago
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lord [1]

Answer: 5:8

Step-by-step explanation:

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(There can be many answers to your question but the one i told you is the most reduced one)

7 0
3 years ago
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