If the number is divisible by 6 color it brown, all other numbers color orange

Question

Marta_Voda [28]

The equation that shows the profit earned for selling popcorn for x hours is y = $15m - $20

From the equation of the linear function given y = mx + b

y indicates the profit earned and x represents the time in hours.

From the question,

After 3 hours, the popcorn stand earned a profit of $25.

∴ The equation becomes $25 = 3m + b ------ (1)

and after 6 hours, the profit was $70.

∴ The equation becomes $70 = 6m + b ------- (2)

Now, we will solve the two equations simultaneously

From the first equation

$25 = 3m + b

We can write that

b = $25 - 3m ------- (3)

Substitute this into the second equation

$70 = 6m + b

We get

$70 = 6m + ($25 - 3m)

$70 = 6m + $25 - 3m

$70 - $25 = 6m - 3m

$45 = 3m

∴ m = $45 ÷ 3

m = $15

Now, substitute the value of m into equation (3)

b = $25 - 3m

b = $25 - 3($15)

b = $25 - $45

b = -$20

∴ m = $15 and b = -$20

Putting these values into the equation y = mx + b we get

y = $15m +(- $20)

∴ y = $15m - $20

Hence, the equation that shows the profit earned for selling popcorn for x hours is y = $15m - $20

Learn more here: brainly.com/question/19511111

5 0

2 years ago

The line with equation −a+3b=0 coincides with the terminal side of an angle θ in standard position and sinθ<0 .

Anna11 [10]

If $a$ is the variable of the horizontal axis, then you can solve for $b$ to get the equation of the line in slope-intercept form in the $a,b$ plane:

$-a+3b=0\implies b=\dfrac a3$

i.e. a line with slope $\dfrac13$ through the origin, which means it is contained in the first and third quadrants. Since the terminal side of $\theta$ has a negative sine, the angle must lie in the third quadrant.

Because the slope of the line is $\dfrac13$ , you can choose any length along the line to make up the hypotenuse of a right triangle with reference angle $\theta$ . Any such right triangle will have $\tan\theta=\dfrac13$ , regardless of whether the angle is the first or third quadrant. But since $\theta$ is known to lie in the third quadrant, and so $\sin\theta$ and $\cos\theta$ are both negative, you have

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac13\implies \dfrac{\sin\theta}{\cos\theta}=\dfrac{-1}{-3}\implies \cos\theta=-3$