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german
2 years ago
12

Help me with this question please and thank you!! :)

Mathematics
1 answer:
DIA [1.3K]2 years ago
8 0

A \cup B represents the set that contains all the elements that are in at least one of the sets, so A \cup B=\{1, 2, 5, 6, 7, 8, 9, 10, 12, 16, 18, 19, 20, 21, 22, 23, 25\}.

We want the complement of this set (in other words, the set with all the elements in the universal set but not in the given set).

This set is {3, 4, 11, 13, 14, 15, 17, 24}

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Let a and b be natural numbers for which a divides<br> b. then a is less than or equal to b
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8 0
3 years ago
Which expression has a value of -6 A. -4 • 2 - (-14) B. -16 divided by (-2) - (-2) C. -2 - (-8) divided by (-1) D. -12 divided b
tatiyna

Answer:

its B. -16 divided by (-2) - (-2)

8 0
3 years ago
If a+b+c =0 show that a³+b³+c³= 3abc
slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=

2*[3abc-(a^3+b^3+c^3)]=0

so 3abc-(a^3+b^3+c^3)=0

so a^3+b^3+c^3=3abc

7 0
3 years ago
Explain how counting number of girls in five children family can be treated as a binomial experiment. What assumptions are neces
Juliette [100K]

This is a binomial experiment and you'll use the binomial probability distribution because:

  1. There are two choices for each birth. Either you get a girl or you get a boy. So there are two outcomes to each trial. This is where the "bi" comes from in "binomial" (bi means 2).
  2. Each birth is independent of any other birth. The probability of getting a girl is the same for each trial. In this case, the probability is p = 1/2 = 0.5 = 50%
  3. There are fixed number of trials. In this case, there are 5 births so n = 5 is the number of trials.

Since all of those conditions above are met, this means we have a binomial experiment.

Some textbooks may split up item #2 into two parts, but I chose to place them together since they are similar ideas.

8 0
3 years ago
A bakery sold a total of 3028 coffee buns and blueberry buns. 1560 more coffee buns were sold than the blueberry buns. How many
Natali [406]

Answer:

\large{ \tt{ -  \: HEY  \: AH~\:♡ }}

\large{ \tt{✺ \: SOLUTION}} :

  • Provided : Total sold bakery items : 3028 coffee buns and blueberry buns & 1560 more coffee buns were sold than the blueberry buns.

  • To find : Number of coffee buns the bakery sold

- First , Subtract 1560 from 3028 :

\large{ \tt{→ \: 3028 - 1560 = 1468}}

We just subtacted the number of more coffee buns from the number of told items sold which means that the number of coffee buns and the number of blueberry buns sold are equal for now. Now divide 1428 by 2 :

\large{ \tt{→ \frac{1428}{2} = 734 }}

Now - Let's get back to the second sentence of the question and add 734 & 1560 :

\large{ \tt{→ \: 734 + 1560 =  \large{ \boxed{2294}}}}

  • Hence , The bakery sold 2294 coffee buns.

- Hope this helps , oneesan! ;)

7 0
2 years ago
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