Let L be the length
Let w be the width
Let p be the perimeter
L+w+L+w=p
L=w+20
3L+2w+3L+2w=240
Sub the first equation in for L in the second equation and solve for w
3(w+20)+2w+3(w+20)+2w=240
3w+60+2w+3w+60+2w=240
10w+120=240
10w=240-120
10w=120
W=120/10
W=12
Sub w into the first equation and solve for L
L=w+20
L=12+20
L=32
Hope this helps!
Answer:127 pages of paper
Step-by-step explanation:
18 times 7
Answer:
b c d
Step-by-step explanation:
So your variable are these
x= # of accountants
x+10= # of supervisors
4(x+10)= # of mechanics
So you get the equation x+ (x+10) + (4x+40) = 230
and you solve for x
6x + 50 = 230
6x = 180
x=30
so accountants = 30
supervisors = 40
Mecahnics = 160
