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lana [24]
2 years ago
14

How to multiply a whole number by a fraction like 4/6 x 4 etc .​

Mathematics
1 answer:
jeka57 [31]2 years ago
6 0

Answer:

See below, please!

Step-by-step explanation:

To multiply a whole number by a fraction, set up both numbers so that they have a numerator and denominator, multiply the corresponding parts, and simplify.

Ex: \frac{4}{6}*\frac{4}{1}. Both of them are in fraction form, right? Now multiply the numerator and denominator together. Doing this, you get 16/6. Now simplify. Look for a common factor between both the numerator and denominator. We can see that one common factor is 2. So, our simplified fraction is 8/3.

Hope this helped!  

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A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul
pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

\hat p = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion  is given by;

     P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.6858

           n = sample of respondents = 2,610

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at

                                   2.5% level of significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }]

  = [ 0.6858-1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } , 0.6858+1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } ]

  = [0.668 , 0.704]

Therefore, 95% confidence interval for the population proportion of the adults is (0.668, 0.704).

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3 years ago
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How to do you add probability
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To add the probabilities, you would have to treat them like any other numbers. If they are decimals or percents, you can follow basic addition rules. If you are given the probabilities as fractions, make sure that you have common denominators when you add them.
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Will there be more thaan one relay exchange between 2 consecutive tenths of a mile​
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Yes there will be more than one

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Please answer this correctly without making mistakes
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Answer:

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Step-by-step explanation:

I'm guessing on this one but maybe because a whole number has no remainder

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