Answer:
Check the explanation
Explanation:
when calculating the total time to send the I bits of information or The packet delivery time or latency which can be said to be the amount of time from when the first bit leaves the point of transmission until the last is received. When it comes to a physical link, it can be computed or determined as: Packet delivery time = Transmission time + Propagation delay.
Kindly check the attached image below to get the step by step explanation to the above question.
Answer:
The correct output of this question is "Sneezy Sleepy".
Explanation:
In the given code firstly we create the object of the integer class that is first in this we pass the integer value that is 7. Then we declare another second integer variable is this variable we pass object as a reference. Then we use the two conditional statements. In the first, if block we check that the object of the class is equal to the reference variable. If it is true it prints Sneezy. otherwise, it will print Grumpy. In second if block we check that the object of the class is equal to the reference variable. but in this time we the equals() function it is the same as(==). If the condition is true it prints Sleepy. otherwise, it will print Doc. So the output of the code is Sneezy Sleepy.
<span>The statement that IPv6 includes a native information security framework (IPsec) that provides both data and control packets is false.
</span>IPSec is a mandatory component for IPv6, and is used to natively protect IPv6 data <span>as it is sent over the network,. and not control packets.
</span>The IPv6 IPSec is a set of Internet standards that uses cryptographic security services to provide confidentiality ,data origin authentication and data integrity<span>
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Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
Answer:
Size
Explanation:
Connectivity, they need internet to work.
Speed, they need it to work fast.
Storage, they need space to work.
Size, isn't all that important, unlike the rest.
