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2 years ago

What is the different between the patch Tool and the Headling Brush tool?

Computers and Technology

1 answer:

KonstantinChe [14]2 years ago

7 0

Answer:

Explanation:

The Healing Brush and Patch tools add extra features. They match the texture, transparency, lighting, and shading of the sampled area. Instead of replacing them, pixel for pixel, like the clone stamp. This causes the painted pixels to blend seamlessly into the rest of the image. Using the Healing Brush tool: 1. Select the Healing Brush tool in the toolbox.

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In the Happy Valley School System, children are classified by age as follows:less than 2, ineligible2, toddler3-5, early childho

Greeley [361]

Answer:

int age = 10;

switch (age){

case 0:

case 1:

System.out.println("ineligible");

break;

case 2:

System.out.println("toddler");

break;

case 3:

case 4:

case 5:

System.out.println("early childhood");

break;

case 6:

case 7:

System.out.println("young reader");

break;

case 8:

case 9:

case 10:

System.out.println("elementary");

break;

case 11:

case 12:

System.out.println("middle");

break;

case 13:

System.out.println("impossible");

break;

case 14:

case 15:

case 16:

System.out.println("high school");

break;

case 17:

case 18:

System.out.println("scholar");

break;

default:

System.out.println("ineligible");

}

Explanation:

In java and many other programming languages, a switch statement is a way of having multiple branching options in a program. This is usually considered a more efficient way than using multiple if....else if statements. and the expression variables could be byte, char int primitive data types. etc. every branch (option) in a switch statement is followed by the break statement to prevent the code from "falling through". In the question The variable age is declared as an int and initialized to 10. and tested against the conditions given in the question.

7 0

3 years ago

Consider the following Stack operations:

maxonik [38]

Answer:

Sequence of popped values: h,s,f.

State of stack (from top to bottom): m, d

Explanation:

Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:

push(d) -> enters d to the Stack

Stack:

d ->top

push(h) -> enters h to the Stack

Stack:

h ->top

d ->bottom

pop() -> removes h from the Stack:

Stack:

d ->top

p: Suppose p contains popped values so first popped value entered to p is h

p = h

push(f) -> enters f to the Stack

Stack:

f ->top

d ->bottom

push(s) -> enters s to the Stack

Stack:

s ->top

d ->bottom

pop() -> removes s from the Stack:

Stack:

f ->top

d -> bottom

p = h, s

pop() -> removes f from the Stack:

Stack:

d ->top

p = h, s, f

push(m) -> enters m to the Stack:

Stack:

m ->top

d ->bottom

So looking at p the sequence of popped values is:

h, s, f

the final state of the stack:

m, d

end that is the top of the stack:

6 0

3 years ago

Write a statement to add the key Tesla with value USA to car_makers. Modify the car maker of Fiat to Italy. Sample output for th

marishachu [46]

Answer:

Input code:

car_makers = {'Honda': 'Japan', 'Fiat': 'Germany'}

#add Tesla and USA as corresponding value

car_makers['Tesla'] = 'USA'

#change Fiat entry to Italy instead of Germany

car_makers['Fiat'] = 'Italy'

print(car_makers)

print('Honda made in', car_makers['Honda'])

print('Fiat made in', car_makers['Fiat'])

print('Tesla made in', car_makers['Tesla'])

Explanation:

The first line is a define object in the python code, containing two entries of Honda and Fiat and their respective countries.

The python code adds an entry to the object "car maker" using the bracket notation, the tesla car from USA.

The country of the Fiat car is changed from Germany to Italy, using the bracket notation.

The output of the complete object and the individual cars is given.

<u>output of the python code:</u>

{'Honda': 'Japan', 'Fiat': 'Italy', 'Tesla': 'USA'}

Honda made in Japan

Fiat made in Italy

Tesla made in USA.

7 0

3 years ago

Function Integer cube(Integer num) Return num * num * num End Function Write a main module that contains a statement that passes

Klio2033 [76]

Answer:

#include <iostream>

using namespace std;

int cube(int num)//function cube..

{

return num*num*num;

}

int main() {

int result=cube(4);//result stores the value of cube(4).

cout<<result;//displaying it to the screen.

return 0;

}

Explanation:

The above code is in C++ language.The function cube is passed with value 4 and the result of it is stored in the variable result of integer type.Then the result is displayed using the cout. Which is used to print the statement to the output screen.

5 0

3 years ago

Draw a timeline for each of the following scheduling algorithms. (It may be helpful to first compute a start and finish time for

12345 [234]

Answer:

See explanation below

Explanation:

Previos concepts

First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".

Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".

Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".

Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"

Solution for the problem

Assuming the dataset given on the plot attached.

Part a

For this algorithm the result would be:

Job A 0-6

Job B 6-(6+3) = 6-9

Job C 9-(9+1) = 9-10

Job D 10-(10+4) = 10-14

Part b

For this algorithm the result would be:

Job A 0-6

Job C 6-(6+1) = 6-7

Job B 7-(7+3) = 7-10

Job D 10-(10+4) = 10-14

Part c

For this algorithm the result would be:

Job A 0-1 until 14

Job B 2-(2+3) = 2-5

Job C 3-(3+2) = 3-5

Job D 9-(9+5) = 9-14

Part d

For this algorithm the result would be:

Job A 0-2 , 7-9, 12-14

Job B 2-4, 9-10

Job C 4-(4+1) = 4-5

Job D 5-7, 10-12

8 0

3 years ago

What is the different between the patch Tool and the Headling Brush tool?​

What is the different between the patch Tool and the Headling Brush tool?