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3 years ago

The school is having a dance as a fundraiser. Tickets cost $. Each

Mathematics

2 answers:

Art [367]3 years ago

6 0

Answer:

How are we supposed to know .???

we can only see half of the problem

Step-by-step explanation:

g100num [7]3 years ago

6 0

Can u give me the rest of the question please if not this for the free point

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A bakery sold a total of 400 cupcakes in a day, and 43% of them were vanilla flavored. how many of the cupcakes sold that day we

garik1379 [7]

The number of the cupcakes sold that day that were vanilla flavored is 172.

<h3>How do we calculate a number from a percentage?</h3>

The number of the cupcakes sold that day that were vanilla flavored can be calculated using the following formula:

Number of vanilla flavored cupcakes sold = Total number of cupcakes sold * Percentage that were vanilla flavored .............. (1)

Substituting the relevant values into equation (1), we have:

Number of vanilla flavored cupcakes sold = 400 * 43% = 172

Learn more about percentages here: brainly.com/question/14801224.

#SPJ1

7 0

2 years ago

Please help!!! i cant figure it out

GenaCL600 [577]

Step-by-step explanation:

Hi there!

Given;

f(x) = 17x + 9

h(x) = 4x

To find: f(x)-h(x)

f(x)-h(x)= 17x + 9 - 4x

= 13x + 9

Therefore, f(x)-h(x) = 13x + 9.

<u>Hope it helps!</u>

4 0

2 years ago

What is the volume of the triangular prism below

cestrela7 [59]

The volume is 4.5 ft^3.

7 0

3 years ago

What is 2/5 times 5/16

melomori [17]

Answer:

1/8

Step-by-step explanation:

7 0

3 years ago

The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi

Tresset [83]

Answer:

P(X \le 250 ) = 0.7564 [/tex] , $P(X < 250 ) = 0.7564$ ,

$P(X < 300 ) = 0.09922$

$P(100 < X < 250 ) =0.644$

$x = 192.1$

Step-by-step explanation:

From the question we are told that

The value for $\alpha = 2.6$

The value for $\beta = 220$

Generally the Weibull distribution function is mathematically represented as

$F( x , \alpha , \beta ) = \left \{ 0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x < 0} \atop { 1- e^{-(\frac{x}{\beta } )^{\alpha } }}\ \ \ \ \ \ x \ge 0} \right$

Generally the probability that a specimen's lifetime is at most 250 is mathematically represented as

$P(X \le 250 ) = F(250, 2.7 , 220 )$

$P(X \le 250 )=1 - e^{- (\frac{250}{220} )^{2.7}}$

$P(X \le 250 ) = 1 - 0.2436$

$P(X \le 250 ) = 0.7564$

Generally the probability that a specimen's lifetime is less than 250

$P(X < 250 ) = F(250, 2.7 , 220 )$

[texP(X < 250 ) =1 - e^{- (\frac{250}{220} )^{2.7}}[/tex]

$P(X < 250 ) = 1 - 0.2436$

$P(X < 250 ) = 0.7564$

Generally the probability that a specimen's lifetime is more than 300

$P(X > 300 ) = 1- p(X \le 300 )$

$P(X > 300 ) = 1- F(300, 2.7 , 220 )$

[texP(X < 300) =1- [1 - e^{- (\frac{300}{220} )^{2.7}}][/tex]

$P(X < 300 ) = 0.09922$

Generally the probability that a specimen's lifetime is between 100 and 250 is

$P(100 < X < 250 ) = P(X < 250) - P(X < 100)$

=> $P(100 < X < 250 ) =F(250 , 2.7 , 220 ) - F(100 , 2.7 , 220 )$

=> $P(100 < X < 250 ) =(1 - e^{-(\frac{250}{220})^{2.7}}) - (1 - e^{-(\frac{100}{220})^{2.7}})$

=> $P(100 < X < 250 ) = (1 - 0.244 ) - (1- 0.888)$

=> $P(100 < X < 250 ) =0.644$

Generally the value such that exactly 50% of all specimens

$P(X > x) = 1-P(X < x) = 0.50$

=> $P(X > x) = 1- (1 - e^{- (\frac{x}{220}) ^{2.7}}) = 0.50$

=> $P(X> x ) = e^(- \frac{x}{20})^{2.7} = 0.50$

=> $P(X> x ) = (- \frac{x}{20})^{2.7} = ln0.50$

=> $P(X> x ) = \frac{x}{20} =[ -ln0.50 ] ^{frac{1}{2.7}}$

=> $x = 220[ -ln0.50 ] ^{frac{1}{2.7}}$

=> $x = 192.1$

8 0

3 years ago