In this question, it is given that the measurement of angles USW and TSR are 7x-34 and 4x+9 .
First we have to find the relationship between those two angles .
And these angles are vertical opposite angles which are congruent .
Therefore
Therefore measurement of angle USW is
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
B. 1,188 cubic units
Step-by-step explanation:
First find the area of the base
A = 1/2b*h (this would only be half the base so our formula would be)
A = b*h (Now enter values)
A = (9)(6)
A = 54 (now plug this into the volume formula)
V = Ab * h
V = (54)(22)
V = 1,188 cubic units
Let the number of 250g=0.25 kg jars be x and that of 500g=0.5 kg jams be y;
therefore:
total number of jars ws
x+y=511
x=511-y..........i
total mount kgs was:
0.25x+0.5y=186.5....ii
substituting i in ii
0.25(511-y)+0.5y=186.5
127.75-0.25y+0.5y=186.5
solving for y we get:
0.25y=186.5-127.75
0.25y=58.75
y=58.75/0.25
y=235 jars
and
x=511-x
=511-235
=276
hence we conclude that there was 235 jars with 0.5 kg almond and 276 jars with 0.25 kg almonds
