The ladder and the outside wall form a right triangle
The length of the ladder is 97.8 feet
<h3>How to determine the
length of the
ladder?</h3>
The given parameters are:
Distance (B) = 22 feet
Angle of elevation (θ) = 77 degrees
The length (L) of the ladder is calculated using the following cosine ratio
cos(θ) = B/L
So, we have:
cos(77) = 22/L
Make L the subject
L = 22/cos(77)
Evaluate the product
L = 97.8
Hence, the length of the ladder is 97.8 feet
Read more about right triangles at:
brainly.com/question/2437195
Answer:
Step-by-step explanation:
I think its substitution
Answer:
a) 25 is 3 standard deviation from the mean
b) Is far away from the mean, only 0,3 % away from the right tail
c) 25 is pretty close to the mean (just a little farther from 1 standard deviation)
Step-by-step explanation:
We have a Normal Distribution with mean 16 in.
Case a) we also have a standard deviation of 3 inches
3* 3 = 9
16 (the mean) plus 3*σ equal 25 in. the evaluated value, then the value is 3 standard deviation from the mean
Case b) 25 is in the range of 99,7 % of all value, we can say that value is far away from the mean, considering that is only 0,3 % away from the right tail
Case c) If the standard deviation is 7 then
mean + 1*σ = 16 + 7 =23
25> 23
25 is pretty close to the mean only something more than 1 standard deviation
Answer:
Part 1)
Bob's mistake was to have used the cosine instead of the sine
The measure of the missing angle is 
Part 2) The surface area of the pyramid is 
Step-by-step explanation:
Part 1)
Let
x----> the missing angle
we know that
In the right triangle o the figure
The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle
Bob's mistake was to have used the cosine instead of the sine
Part 2) we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
where
b is the length side of the square
h is the height of the triangular lateral face
In this problem
-------> by an 45° angle
so
Find the value of b
Find the surface area
![SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}](https://tex.z-dn.net/?f=SA%3D12%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%2812%29%286%29%5D%3D288%5C%20cm%5E%7B2%7D)
