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White raven [17]
4 years ago
7

Find the equation of a line passing through (3, -5) that is parallel to 2x+6y=10

Mathematics
1 answer:
Zina [86]4 years ago
4 0

Answer:

The equation of the line would be y = -1/3x - 4

Step-by-step explanation:

In order to find this, we first need to find the slope of the original line. We do this by solving for y.

2x + 6y = 10

6y = -2x + 10

y = -1/3x + 5/3

Now that we see the slope as -1/3, we know the new line will have the same slope thanks to the definition of parallel lines. So, we can use this slope and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - -5 = -1/3(x - 3)

y + 5 = -1/3x + 1

y = -1/3x - 4

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Answer:

It says to Graph y = 1/2x - 4

So equation y = 1/2x - 4

this corresponds to slope intercept form which is y = mx + b

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B =  y - intercept

First, start at the origin, (0,0)

Then go down 4, you should now be on the coordinate (0,4)

Now we need to use the slope.

The slope is 1 / 2, this means rise 1, run 2 (in this case 2 to the right because it is positive)

So, start at (0 , 4) and go up 1 unit then 2 to the right, then place a dot, keep repeating until you meet the end of the paper.

Then do the opposite so that you can graph the other side.

Down 1 and 2 to the left.

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