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svlad2 [7]
3 years ago
7

can yall do me a favor, i know this random but i got played by someone so can u spaam his ig, acc name is sturdyyyyy_ just spam

his comments called him a cheater and tell him he weird. please. females help a person out.
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

okkkkk

Step-by-step explanation:

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Arnie's car used 100 cups of gasoline during a drive. He paid $3.12per gallon for gas how much did the gas cost
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Okay so in a gallon there are 16 cups, in this case 100 cups is equivalent to 6.25 gallons. 6.25 times 3.12= 19.5 

Therefore $19.5 is how much the gas cost!
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What is the volume of the right rectangular prism with a length of 18 inches, a width of 4 inches, and a height of 10 inches? 32
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Every 18 miles he uses 3 gallons

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Bottles filled by a certain machine are supposed to contain 12 oz of liquid. In fact the fill volume is random with mean 12.01 o
stepan [7]

Answer:

27.43% probability that the mean volume of a random sample of 144 bottles is less than 12 oz.

Step-by-step explanation:

To solve this problem, it is important to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 12.01, \sigma = 0.2, n = 144, s = \frac{0.2}{\sqrt{144}} = 0.0167

What is the probability that the mean volume of a random sample of 144 bottles is less than 12 oz

This is the pvalue of Z when X = 12

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{12 - 12.01}{0.0167}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743.

So there is a 27.43% probability that the mean volume of a random sample of 144 bottles is less than 12 oz.

4 0
3 years ago
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