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3 years ago

Please help pick which option. I will mark brainlist.

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

5 0

Answer:

A is the answer......

because the common denominator for 12 and 60 is 5

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Mei bought a box of markers for b dollars, a shoulder bag that cost twice as much as the box of markers and a pen that cost $6 l

Masteriza [31]

Box of markers = $ B

Shoulder bag = Twice as much as the box of markers = $ 2B

Pen = Six less than the shoulder bag = $ (2B - 6)

Hence, the cost of pen is $ (2B - 6).

3 0

3 years ago

Kate made an 85 on her English test. Her grade on the English test was 37 points less than twice the grade on her Science test.

Irina18 [472]

The grade of her sci test was 61. First I add 37 to 85, the sum being 122. Then if you divide it in half, you get the quotien and final answer of 61

7 0

3 years ago

Read 2 more answers

Where would 3.8 go on the number line?

nata0808 [166]

Answer:

Between 3 and 4

Step-by-step explanation:

3 0

3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago

How can I solve 2x+y=-3

Vladimir79 [104]

Answer:

If solving for x then x = -3/2 +y/2

If solving for y then y = -3-2x

Step-by-step explanation:

For x: Divide both sides by 2

For y: Subtract 2x from both sides of the equation

4 0

3 years ago