If b is in the first position then c can be in any 1 of the remaining 6 positions.
If we start with ab then the letter c can be in any one of 5 positions and if we have aab there are 4 possible positions for c and so on.
So the total number of possible sequences where b comes first = 6+5+4+3+2+1 = 21.
The same argument applies when c comes before b so that gives us 21 ways also.
So the answer is 2 *21 = 42 different sequences.
A more direct way of doing this is to use factorials:-
answer = 7! / 5! = 7 * 6 = 42.
( We divide by 5! because of the 5 a's.)
Answer:
subtract 2 and add 3
Step-by-step explanation:
8-2=6
6+3=9
9-2=7
7+3=10
I believe it would be the last answer, 6.25
if this is correct i’m very sorry, but if this helps, please mark brainliest. :)
The most appropriate choice for simple interest will be given by- Balance of Jose after 1 year is $1050
What is simple interest?
Simple interest is the interest applied on the principal value after charging some certain percentage of rate for some certain amount of time.
If the principal value is p, rate is r % per annum and time is t years
Simple interest is calculated as
SI = p ₓ r ₓ t / 100
Here,
Principal for Jose = $1000
Rate = 5%
Time = 1 year
Simple interest = 1000x5x1/100
= $50
Amount = $(1000+50)
= $1050
Balance of Jose after 1 year is $1050
To learn more about simple interest, refer to the link:
brainly.com/question/25793394
#SPJ10
