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torisob [31]
3 years ago
14

Jonas and four friends go to the fair. Each person buys a fair ticket for $9, a snack for $6, and a drink for $4. Determine the

total cost for everyone.
Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Find the total for what each person spent:

9 + 6 + 4 = $19

Multiply what each person spent by the number of people:

19 x 5 = $95 total

Sindrei [870]3 years ago
5 0

Answer:

i would say 19 because 9+6=15 and 15+4 =19$ on each person so 19 times 5 95 $ in total

Step-by-step explanation:

You might be interested in
If you have a $54.40 balance in your checking account, and you make a deposit of $150.00, what will the new balance be?A. $194.4
yarga [219]
Simply add the two numbers;

Beginning Balance:  $   54.40
Add: cash deposit   <u> $ 150.00</u>
Ending Balance        $ 204.40

ANSWER IS C. $204.40


7 0
3 years ago
Calculate the amount and compound interest on Rs 5000 compounded annually or 2 years 6 months at the rate of 10% per annum.
cluponka [151]

Answer:

Amount

Rs 6345.30

Compound interest

Rs 1,345.30

Step-by-step explanation:

Here in this question, we are interested in calculating the amount and the compound interest on the value given.

To calculate the amount, we use the formula below;

A = P(1 + r/n)^nt

Where; A is the amount which we want to calculate

P is the principal which is Rs 5,000

r is the interest rate per annum = 10% = 10/100 = 0.1

n is the number of times per year in which it is compounded ( since it is annually, then it is 1)

t is the number of years which is 2.5 years( kindly know that 6 months is same 1/2 year , so 6 months is same as 0.5, and thus 2 years 6 months becomes 2.5 years)

now let’s substitute all these values;

A = 5000(1 + 0.1/1)^(1*2.5)

A = 5000(1 + 0.1)^2.5

A = 5000(1.1)^2.5

A = 6,345.2935314294

This is approximately Rs 6,345.30

The second part of the question asks to calculate compound interest

Mathematically ;compound interest = Amount - principal

= 6345.3 - 5000 = Rs 1,345.30

7 0
4 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
The ratio of 96/3 please help
docker41 [41]
\frac{96}{3}= \frac{ \frac{96}{3} }{ \frac{3}{3} }= \frac{32}{1}   =32
7 0
3 years ago
Which value is equivalent to
Ksenya-84 [330]

Answer:

\frac{25}{144}

Step-by-step explanation:

(\frac{7 * 5 * 2}{7 * 3} )^2 * (\frac{5^0}{2^-3})^3 * 2^{-9}

Simplified becomes;

(\frac{10}{3})^2 * 2^3 * \frac{1}{2^9}

Simplifying further gives; \frac{25}{144}

6 0
3 years ago
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