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kolezko [41]
3 years ago
7

ennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month th

an the month before. She ended up saving $19,779.00. How much more did she save each month?
Mathematics
1 answer:
crimeas [40]3 years ago
3 0
The is an arthitmetic sequence, so let's determined all the aspects and factors using the details and information from this word problem.
The first term (a) = 11, number of terms (n) = 57, the sum of nth term (Sn) = 19,779.
Let the common difference between the amount of money she saved more each month is d.
Sn = n/2(2a+(n-1)d)
19,799 = 57/2(2(11) + (57-1)d)
19,799 = 28.5(22 + 56d)
19,799 = 627 + 1,596d
    -627  -627
____________________
   19,172 = 1,596d
___________________
             1,596

d= 12.01253.

In conclusion, she saved about $12 more each month.
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Answer:

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The other part of answer choice A is x = -1/2. We can test this to make sure it works:

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Answer:

1). System of equations- D + Q = 90 and D + 2.5Q = 175.50

2). There are 33 dimes and 57 quarters in the bank.

Step-by-step explanation:

Dylan has a bank that sorts coins as they are dropped in it.

A panel shows the total number of coins inside as well as the total value of these coins.

Let the number of dimes in the bank = D

and the number of quarters in the bank = Q

If the panel shows total number of coins = 90

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And the panel displays the amount of the coins = $17.55

Then equation will be

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D + 2.5Q = 175.50 ------------(2)

Now we subtract equation (1) form equation (2)

D + 2.5Q - (D + Q) = 175.50 - 90

D + 2.5Q - D - Q = 85.5

1.5Q = 85.5

Q = \frac{85.5}{1.5}

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By putting Q = 57 in the equation (1)

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D = 90 - 57 = 33

Therefore, there are 33 dimes and 57 quarters in the bank.

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