Question

Solve 1 over 36 = 6x−3. (1 point)

Answer 1

To solve this problem you must apply the proccedure shown below;

1. You have the following equation given in the problem above:

$\frac{1}{36} = 6^{(x-3)}$

2. You must apply logarithm at both sides of the equation, then, you need to apply the logaritms properties to solve for $x$ and calculate its value, as following:

$log(\frac{1}{36} )=log6^{(x-3)} \\ log(\frac{1}{36} )=(x-3)log(6)\\ x=[\frac{log(\frac{1}{36} )}{log(6)} ]-3\\ x=1$

Therefore, the answer is: $x=1$