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natita [175]
3 years ago
12

is it possible for a system with linear equation and one expontential equation to have two solutions? If so sketch a graph

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
4 0
Yes, it is possible. Please see the attached photo for an example.

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Solve using elimination -x+4y=-19 -3x+3y=6
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Answer:x = -9, y = -7

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Equation 1)  -x + 4y = -19

Equation 2)  -3x + 3y = 6

Multiply ALL of equation 1 by 3 so that both equations include -3x in it.

1)  3(-x + 4y = -19)

Simplify.-3x + 12y = -57  → equation 3

Now, subtract equation 3 from equation 2.

-3x + 12y = -57    

(-)-3x + 3y = 6

Simplify.

9y = -63

Divide both sides by 9.

9y ÷ 9 = -63 ÷ 9

Simplify.

y = -7

Now that we have the value for y, simply plug in -7 for y into equation 1.

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Simplify.-x - 28 = -19

Add 28 to both sides of the equal sign.

-x - 28 + 28 = -19 + 28

Simplify.-x = 9

Divide both sides by -1.x = -9

Now we know that : x = -9, y = -7

To check our work, simply plug in -9 for x and -7 for y into equation 1.

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Simplify.

9 - 28 = -19-19 = -19

Therefore, x = -9, y = -7

Hope this helped! :)

5 0
3 years ago
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