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4 years ago

What is the product of 3x1/5?

Mathematics

1 answer:

vagabundo [1.1K]4 years ago

7 0

Answer: 3/5

Step-by-step explanation: 1/5*3=1/5+1/5+1/5=3/5

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Find the inverse of y = 5x + 6

Scorpion4ik [409]

Answer:

f^-1(x)= x/5 - 6/5

Step-by-step explanation:

Interchange the variable

x= 5y + 6

Solve for Y

y = x/5 - 6/5

8 0

3 years ago

Solve 2sin2(x) – 5sin(x) – 3 = 0. Let u = sin(x). Which of the following is equivalent to the given equation?

Orlov [11]

Answer:

$x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

Step-by-step explanation:

Consider the equation

$2\sin^2x-5\sin x-3=0$

Substitute

$u=\sin x$

into the equation:

$2u^2-5u-3=0$

This is quadratic equation, where

$D=(-5)^2-4\cdot 2\cdot (-3)=25+24=49\\ \\\sqrt{D}=7$

Hence,

$u_1=\dfrac{-(-5)-\sqrt{D}}{2\cdot 2}=\dfrac{5-7}{4}=-\dfrac{1}{2}\\ \\u_2=\dfrac{-(-5)+\sqrt{D}}{2\cdot 2}=\dfrac{5+7}{4}=3$

Now, use the substitution again:

1. When $u_1=-\dfrac{1}{2},$ then

$\sin x=-\dfrac{1}{2}\\ \\x=(-1)^k\sin^{-1}\left(-\dfrac{1}{2}\right)+\pi k,\ k\in Z\\ \\x=(-1)^k\cdot \left(-\dfrac{\pi}{6}\right)+\pi k,\ k\in Z\\ \\x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

2. When $u_2=3,$ then

$\sin x=3$

This equation has no solutions, because the range of $\sin x$ is $[-1,1]$ and 3>1.

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Answer:

Df=[-7,∞)

Step-by-step explanation:

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GalinKa [24]

Answer:

It's $\frac{2}{9}$ and $\frac{5}{6}$

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2 years ago

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10 2/3 + 2h < 4 1/3.

Snezhnost [94]

Well i got -19/6 but if you simplify it it would be -3.16667

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4 years ago

What is the product of 3x1/5?​

What is the product of 3x1/5?