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zavuch27 [327]
3 years ago
9

3 is the____ termconstant or variable ​

Mathematics
2 answers:
Lilit [14]3 years ago
8 0

Answer:

<em><u>Constant</u></em>

Step-by-step explanation:

<h2>HOPE IT WILL HELP YOU ✌✌</h2>
kherson [118]3 years ago
7 0

\huge\mathcal\colorbox{yellow}{{\color{blue}{AnSwEr~↓~↓~}}}

\huge\mathbb\colorbox{black}{\color{white}{constant}}

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Which equation represents a linear function that has a slope of 5 and a y-interceptof-6?
Alexus [3.1K]

Answer:

y=5x-6

Step-by-step explanation:

Comparing y=5x-6 with y=mx+c,the slope is 5 and y intercept is-6

6 0
3 years ago
Pls helpppp!!! I will give brainliest.
pashok25 [27]

Answer:

Step-by-step explanation:

The domain represents the x-values

The range represents the y-values

Domain             Range

  3                        7

                            8

                            -2

                             4

                             1

This relation is not a function because the domain value was used more than one time.  

8 0
3 years ago
The distance between capeton &amp; Jonesville is 80 miles. The scale on the map is 0.75 in 10 Mi how far part are the cities on
ikadub [295]

Answer:

6 in = 80 miles

Step-by-step explanation:

Given that:

Distance between Capeton and Jonesville = 80 miles.

Map scale : 0.75 in = 10 miles ; this means 0.75 inches on the map represents 10 miles on land.

Hence, If ;

0.75 inches = 10 miles

x inches = 80 miles

Cross multiply :

10 * x = 80 * 0.75

10x = 60

10x / 10 = 60 / 10

x = 6 inches

Hence,

6 in = 80 miles

4 0
3 years ago
If Shannon wants to fill a spherical balloon so that it has a circumference of 8π in, how much air will she need to use to fill
lapo4ka [179]

The Volume of air needed for a spherical balloon of radius 4 inch and circumference 8π is 85.3 cubic inch

<h3>Volume of Sphere</h3>

Given Data

  • Circumference = 8π

Let us find radius

circumference = 2πr

8π = 2πr

8 = 2r

r = 8/2

r = 4 inch

Let us find the volume of the sphere

Volume = 4/3πr^3

Volume = 4/3* π*4^3

Volume = 4/3*π64

Volume = 256π/3

Volume = 85.3 cubic inch

Learn more about volume of sphere here:

brainly.com/question/22807400

4 0
2 years ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9
Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that \mu = 8.9, \sigma = 2.9

Sample of 37:

This means that n = 37, s = \frac{2.9}{\sqrt{37}}

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}

Z = -0.53

Z = -0.53 has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

Z = \frac{X - \mu}{s}

Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}

Z = -3.08

Z = -3.08 has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

7 0
2 years ago
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