6 possible ways to order 3 couples in a row
Given,
We have three married couples. that is six persons in total.
a, b, c, d, e, f may taken as the six persons.
Considering the statement:
Elder partner on the left, assume a, c and e as elders.
Then we have, (a, b) ------ ( 1)
(c, d) ------ (2)
(e, f) ------ (3)
There is no change in position between the couples.
So, we get three persons in total.
Possible ways to order these three persons will be like this: 3! = 3×2×1
= 6
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