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BartSMP [9]
3 years ago
5

Mr. Dean has an even number of cats and an odd number of dogs. Show how many dogs and cats he might have

Mathematics
1 answer:
kirill115 [55]3 years ago
6 0
1 dog and 2 cats..................................
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Solve using the method of elimination , determine if the system has 1 solution, no solutions, or infinite solutions
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Compute <br><br> I need help
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(\sqrt{3}-\sqrt{6}+\sqrt{12}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-2\sqrt{6})\times \frac{\sqrt{6}}{2} \\ ((\sqrt{3}+2\sqrt{3})+(-\sqrt{6}-2\sqrt{6}))\times \frac{\sqrt{6}}{2} \\ (3\sqrt{3}-3\sqrt{6})\times \frac{\sqrt{6}}{2} \\ \frac{(3\sqrt{3}-3\sqrt{6})\sqrt{6}}{2} \\ \frac{3(\sqrt{3}-\sqrt{6})\sqrt{6}}{2}

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Help w #5 !! will mark brainlist
iris [78.8K]

The sum that represents the number of tickets sold if 35 tickets were sold Monday, half of the remaining tickets were sold on Tuesday and 14 tickets were sold on Wednesday.

To start solving this, we can assign t as the variable to the total number of tickets that were sold. So, t = 35 (for Monday) + (t - 35)/2 (for Tuesday) + 14 (for Wednesday). To solve this, we can say t = 49 + (t - 35)/2, or 2t = 98 + t - 35, which equals t = 63. Therefore, 63 tickets were sold total.

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If the two legs of an isosceles right triangle measure 7 in which of the following represents the length of its hypotenuse
anyanavicka [17]

Answer:

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Step-by-step explanation:

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Which equation is equivalent to 16 Superscript 2 p Baseline = 32 Superscript p 3?.
Mrac [35]

The equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

<h3>What is equivalent equation?</h3>

Equivalent equation are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The given equation in the problem is,

16^{2p}=32^{p+3}

Write both the equation in the form of same base number as,

(2^4)^{2p}=(2^5)^{p+3}

The power of the power of a number can be written as product of both the numbers. Thus,

(2)^{4\times2p}=(2)^{5\times(p+3)}\\2^{8P}=2^{5P+15}

This is the required equation.

Now if the base is the same at both side of the expression, then the powers can be compared. Thus,

8p=5p+15

Solve it further to find the value of p as,

8p-5p=15\\3p=15\\p=5

Thus the equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

Learn more about the equivalent expression here;

brainly.com/question/2972832

7 0
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