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3 years ago

Mr. Dean has an even number of cats and an odd number of dogs. Show how many dogs and cats he might have

Mathematics

1 answer:

kirill115 [55]3 years ago

6 0

1 dog and 2 cats..................................

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Which of the following is a true polynomial identity

zhuklara [117]

Answer:

It's a.

Step-by-step explanation:

(a - 2b)^2 + 8ab

= a^2 - 4ab + 4b^2 + 8ab

= a^2 + 4ab + 4b^2.

((a + 2b)^2 = a^2 + 4ab + 4b^2.

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3 years ago

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Evaluate. Show all work<br> 51-(21-5)x2

masya89 [10]

Answer:

Step-by-step explanation:

51-(16)x2

16x2=32

51-32=19

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2 years ago

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Find the product -7(-a2)(-b3)

vlada-n [284]

$-7(-a^2)(-b^3)=\boxed{-7a^2b^3}$

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3 years ago

Two boys and three girls are auditioning to play the piano for a school production. Two students will be chosen, one as the pian

finlep [7]

Answer:

30% is the correct answer.

Step-by-step explanation:

Total number of boys = 2

Total number of girls = 3

Total number of students = 5

To find:

Probability that the pianist will be a boy and the alternate will be a girl?

Solution:

Here we have to make 2 choices.

1st choice has to be boy (pianist) and 2nd choice has to be girl (alternate).

$\bold{\text{Required probability }= P(\text{boy as pianist first}) \times P(\text{girl as alternate})}$

Formula for probability of an event E is given as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

For $P(\text{boy as pianist})$ , number of favorable cases are 2 (total number of boys).

Total number of cases = Total number of students i.e. 5

So, $P(\text{boy as pianist})$ is:

$P(\text{boy as pianist}) = \dfrac{2}{5}$

For $P(\text{girl as alternate})$ , number of favorable cases are 3 (total number of girls).

Now, one boy is already chosen as pianist so Total number of cases = Total number of students left i.e. (5 - 1) = 4

$P(\text{girl as alternate}) = \dfrac{3}{4}$

So, the required probability is:

$\text{Required probability } = \dfrac{2}{5}\times \dfrac{3}{4} = \dfrac{3}{10} = \bold{30\%}$

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3 years ago

Point M is the midpoint of AB . Through point M a line segment XY is drawn, so that both XA and YB are perpendicular to AB . Pro

GaryK [48]

Answer:

See the proof below

Step-by-step explanation:

Let the line AB be a straight line on the parallelogram.

A dissection of the line (using the perpendicular line X) gives:

AY ≅ BX

Another way will be using the angles.

The angles are equal - vertically opposite angles

Hence the line AY ≅ BX (Proved)

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3 years ago

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