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3 years ago

10

Solve using quadratic formula.

xFormula1" title="4 {s}^{2} + 8s + 4 = 0" alt="4 {s}^{2} + 8s + 4 = 0" align="absmiddle" class="latex-formula">

1 answer:

lianna [129]3 years ago

3 0

S = - 1
Hope this help!

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Can someone pls help me the question is in the picture and the answer choices are

Ratling [72]

Sure. We have $E(2t,0)$ and $C(2p,2r)$ so the midpoint M is

$M = \frac 1 2(E+C) = ((2t+2p)/2, (0+2r)/2)=(t+p,r)$

Choice B

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2 years ago

Keenan had p coins. Then he found 60 more coins in a drawer. Write an expression that shows how many coins Keenan has now.

Rudiy27

Answer:

p+60?

Step-by-step explanation:

I hope this is right I say p+60 because once you add p to 60 you get your answer and you don't need to worry about the answer because its an expression not an equation.

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1 year ago

Read 2 more answers

Find intergers to make this statement true _×_=30

Natasha2012 [34]

1x30, 6x5, 3x10, 15x2 here are some.

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3 years ago

Can someone help fast please

Phoenix [80]

Answer:

$\frac{3a}{a-2}$

Step-by-step explanation:

$\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}$

Factorise $2a^2 - 11a + 14}$

$\frac{2a - 7}{a}*\frac{3a^2}{(2a - 7)(a - 2)}$

$2a - 7$ cancels 2a - 7

$\frac{1}{a}*\frac{3a^2}{(1))(a - 2)}$

$\frac{1(3a^2)}{a(a-2)}$

$\frac{a(3a)}{a(a-2)}$

"a" cancels "a"

$\frac{3a}{a-2}$

Thus,

$\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}$ = $\frac{3a}{a-2}$

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2 years ago

The question is in the image

HACTEHA [7]

Answer:

The first one

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

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3 years ago