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Svetlanka [38]
2 years ago
15

Maria drives 130 miles in 2 hours. If she keeps driving at the same speed without stopping, what is the total time it will take

her to drive 650 miles?
Mathematics
2 answers:
Jobisdone [24]2 years ago
5 0

Answer:

10 hours~!

Step-by-step explanation:

zlopas [31]2 years ago
3 0
It would take her 10 hours.

Explanation: 650 divided by 130 is 5 and 2 hours multiplied by 5 hours is 10 hours. Sorry if I got it wrong, but hoped I helped.
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Carry out the indicated operations and simplify where possible:
zzz [600]

Answer:

1/8

Step-by-step explanation:

<u>Solving in steps:</u>

  • x(8x - 8y)⁻¹ + y(8y - 8x)⁻¹ =
  • x/8(x-y) +y/8*(-(x-y))
  • x/8(x-y) - y/8(x-y) =
  • (x -y)/8(x-y) =
  • 1/8

Answer is 1/8

3 0
3 years ago
What is the distance bewteen -7 and 41
Gala2k [10]
To find distance, subtract the largest number from smaller

41 - (-7)

41 + 7 = 48

the distance is 48

hope this helps
3 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
a warehouse has 1,203 shirts to send 3 stores, If each store gets the same number of shirts , how many shirts will go to each st
antiseptic1488 [7]

Answer:

401 shirts

Step-by-step explanation:

1203 divided by 3 equals to 401

7 0
2 years ago
What is the solution to the equation -√(15+x)=-3?
marin [14]
So, the negative would be divided out to make it 3, then square both sides to get rid of the square root and get 9, then subtract 15 and you get -6.  <span />
7 0
2 years ago
Read 2 more answers
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