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zalisa [80]
3 years ago
14

CAN SOMEONE PLEASE WRITE A EQUATION OF THIS LINE!!

Mathematics
2 answers:
serious [3.7K]3 years ago
5 0

Answer (<u>assuming it can be in slope-intercept form)</u>:

y = -x - 1

Step-by-step explanation:

When knowing the slope of a line and its y-intercept, you can write an equation to represent it in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

1) First, find the slope of the equation, or m. Pick any two points from the line and substitute their x and y values into the slope formula, m = \frac{y_2-y_1}{x_2-x_1}. I chose the points (0, -1) and (-1, 0):

m = \frac{(0)-(-1)}{(-1)-(0)} \\m = \frac{0+1}{-1-0} \\m = \frac{1}{-1} \\m = -1

Thus, the slope is -1.

2) Now, find the y-intercept, or b. The y-intercept of a line is the point at which the line crosses the y-axis. By reading the graph, we can see that the line intersects the y-axis at the point (0,-1), therefore that must be the y-intercept.  

3) Now, substitute the found values into the y = mx + b formula. Substitute -1 for m and -1 for b:

y = -x  -1

vampirchik [111]3 years ago
4 0

Answer:

hirap nyan ahhh

Step-by-step explanation:

math hehehhehe

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Read 2 more answers
a chemist has two alloys, one of which is 10% gold and 15% lead and the other of which is 30% gold and 40% lead. how many grams
IrinaK [193]
Let the weight of the first alloy will be x grams.
Weight of gold will be 0.1x grams, weight of lead will be 0.15x grams.
Let the weight of the second alloy <span>will be y grams.
</span><span>Weight of gold will be 0.3y grams, weight of lead will be 0.4y grams.
</span>Summarizing:
0.1x+<span>0.3y=60       - gold
</span><span>0.15x+0.4y=88     - lead
</span>
0.1x+<span>0.3y=60     * 10   
</span><span>0.15x+0.4y=88   * 100
</span>
x+3y=600          * 15
15x+40y=8800

15x+45y=9000      
<span>15x+40y=8800
</span>
<span>15x+45y=9000            /15
</span>45y-40y=9000-8800

x+3y=600     
5y=200

x+3y=600     
y=40

y=40
x=600-3*40=480

y=40    
<span>x=480</span>

↑The answers.

6 0
4 years ago
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