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Kamila [148]
3 years ago
12

Write the equation for the line. ​

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0
The equation for the line is x= -4 because your line is going through the x axis
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A) Work out the value of 5^2-1^5 x 2^4
Mekhanik [1.2K]

Answer: 9

Step-by-step explanation

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3 years ago
The volume of the triangluar block is 4 cubic inches. What is the approximate length of y?
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The volume of the triangluar block is 4 cubic inches. What is the approximate length of y? -- 2.8 inches

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3 years ago
K-10=-24 what is the value of k
pickupchik [31]

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8 0
4 years ago
Read 2 more answers
Write an equation of the line that passes through the point(-6,-9) with slope -5
LUCKY_DIMON [66]

Answer:

  y = -5(x +6) -9

Step-by-step explanation:

The point-slope form of the equation for a line can be written as ...

  y = m(x -h) +k

for a line with slope m through point (h, k).

You have m=-5 and (h, k) = (-6, -9). Filling in these values gives ...

  y = -5(x -(-6)) -9

Simplifying a bit, you get ...

  y = -5(x +6) -9

4 0
4 years ago
Show that the function has at least one zero between x=1 and x=2
ANTONII [103]

Answer:

See Below.

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = 7x^5-9x^4-x^2

And we want to show that it has at least one zero between <em>x</em> = 1 and <em>x</em> = 2.

Because the function is a polynomial, it is everywhere continuous.

Evaluate the function at <em>x</em> = 1 and <em>x</em> = 2:

\displaystyle \begin{aligned} f(1) & = 7(1)^5 - 9(1)^4 - (1)^2 \\ \\ & = -3\end{aligned}

And:

\displaystyle \begin{aligned} f(2) & = 7(2)^5 - 9(2)^4 - (2)^2 \\ \\ & = 76 \end{aligned}

Therefore, because the function changes signs from <em>x</em> = 1 to <em>x</em> = 2 and is continuous on the interval [1, 2], by the intermediate value theorem, there must exist at least one zero in the interval.

7 0
2 years ago
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