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3 years ago

Help pls!!! If a1 = 6 and an 2an-1 then find the value of a4.

1 answer:

3 0

24? I am not entirely sure but I think a4=24

Reason: if a1 equals 6 then I would like to think you would multiply 6 by 4 to get the value of a4 (I haven’t done this type of math in a while)

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B) The perimeter of the shape is 25.71 cm

natita [175]

Answer:

$r=4cm$

Step-by-step explanation:

Having the radius to be involved, the shape is a circle.

<u>Circumference formula </u>

$c=2\pi r$

Finding radius, formula will be reversed.

$r=\frac{25.72cm}{2\pi }$

$r=\frac{25.71cm}{2(3.142)}$ $r=\frac{25.71cm}{6.284}$ $r=4.09cm$

4 0

3 years ago

Clara ran 10 miles, which was twice as far as Nina ran. How far did Nina run?

Anarel [89]

Nina would have ran 5 miles because if clara ran 10 and thats twice as far as nina 10 divided by 2 is 5

4 0

3 years ago

Find a third degree polynomial function of the lowest degree that has the zeros below and whose leading coefficient is one.

Tanzania [10]

Answer:

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is $p(x) = x^{3}-5\cdot x^{2}-6\cdot x$ .

Step-by-step explanation:

From Fundamental Theorem of Algebra, we remember that the degree of the polynomials determine the number of roots within. Since we know three roots, then the factorized form of the polynomial function with the lowest degree is:

$p(x) = (x-r_{1})\cdot (x-r_{2})\cdot (x-r_{3}) = 0$ (1)

Where $r_{1}$ , $r_{2}$ and $r_{3}$ are the roots of the polynomial.

If we know that $r_{1} = -1$ , $r_{2} = 0$ and $r_{3} = 6$ , then the polynomial function in factorized form is:

$p(x) = (x+1)\cdot x \cdot (x-6)$ (2)

And by Algebra we get the standard form of the function:

$p(x) = x\cdot (x+1)\cdot (x-6)$

$p(x) = x\cdot (x^{2}-5\cdot x -6)$

$p(x) = x^{3}-5\cdot x^{2}-6\cdot x$ (3)

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is $p(x) = x^{3}-5\cdot x^{2}-6\cdot x$ .

6 0

2 years ago

If sin=3/5 then what cos equal to

kap26 [50]

$\sin {}^{2} ( \alpha ) + \cos {}^{2} ( \alpha ) = 1$
$\frac{9}{25} + \cos {}^{2} ( \alpha ) = 1$
$\cos {}^{2} ( \alpha ) = \frac{16}{25}$
$\cos( \alpha ) = \frac{4}{5}$

8 0

3 years ago

Read 2 more answers

If /_\CAT ~= /_\LUV then /_\c ~=/_\L. True or False?

marshall27 [118]

Answer:

True

Step-by-step explanation:

They will eat u tho

5 0

3 years ago