Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
Answer:
800 in²
Step-by-step explanation:
Let’s find the area of all the shapes in the net.
10 · 10 = 100
100 · 2 = <u>200</u>
15 · 10 = 150
150 · 4 = <u>600</u>
200 + 600 = <u><em>800</em></u>
Solutions
First Lets solve for this equation
Therefore this given equation is a <span>dependent system.
</span>
<span>Solve for </span>
There are too many solutions to these equations.
I might be wrong but:
x is less than negative three and x is greater than or equal to negative one.
Inequality is x<-3 and x ≥ -1
36.36 is thirty-six and thirty-six hundredths.
36.63 is thirty-six and sixty-three hundredths.
The whole parts are the same. They are both 36.
The decimal parts are 0.63 and 0.36.
Sixty-three hundredths is greater than thirty-six hundredths.
Since 0.63 is greater than 0.36, 36.63 is greater.
