Two cheaper books = x
more expensive = 1.5x
so, 2.5x=150
150/2.5=x=60
therefore the more expensive book = 90
The manager already hired 9 people. Let
be the number of people he still can hire. Since these people will add to the 9 he already hired, when the hiring campaign will be over he will have hired
people. We know that he can't hire more than 14 people, so the number of people hired must be less than or equal to 14:
![9+x \leq 14](https://tex.z-dn.net/?f=%209%2Bx%20%5Cleq%2014%20)
If we subtract 9 from both sides, we have
![x \leq 14-9=5](https://tex.z-dn.net/?f=%20x%20%5Cleq%2014-9%3D5%20)
so, the manager can hire at most 5 other people
Answer:
2.28%
Step-by-step explanation:
As this is normally distributed, we can use z scores to find the percentage.
First, find the z-score for 148.
The z-score that you get is:
(148-160)/2=2
As we see that z=2, we can use a calculator or a z-score chart to find the percentage less than a z score of 2.
I used my chart and found: 2.28%