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kkurt [141]
3 years ago
12

11. On a math exam, two students scored 95, five students scored 87,

Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer:

About 76%.

Step-by-step explanation:

To find the average of numbers, you add all of the numbers together and divide the total by the number of numbers. In this case, your numbers would be 95 twice, 87 five times, 73 three times, 63 four times, and 40 once. The total number of numbers is 15, and the total of all of the exam scores if you add them up is 1136. Finally, you would divide 1136 by 15, which would be 75.7333333, which would be an average of about 76%.

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A bus makes a stop at 2:30, letting off 10 people and letting on 2. The bus makes another stop ten minutes later to let off 3 mo
maksim [4K]

Answer:

Step-by-step explanation:

B

5 0
3 years ago
Do you use the greatest common factor or the least common multiple to add two fractions? In this example what is it? 4/5+5/6 lea
Alenkinab [10]

Answer:

30 is the least common factor or lcm

Step-by-step explanation:

when adding fractions you always have to find the lcm

8 0
2 years ago
Joey walked 10 laps around the school's track. He walked a total distance of 6.74 miles. Monica walked 30 laps around the same t
Anvisha [2.4K]

Answer:

20.22 miles

Step-by-step explanation:

If 10 laps is 6.74 then 30 laps is 3*6.74 which is 20.22

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11 months ago
I need help with these questions
inysia [295]

Answer:

28. m<A=20°, m<B=70°

32. m<A=103°, m<B=77°

Step-by-step explanation:

complementary angle=a+b=90°

supplementary angle=a+b=180°

28. A+B=90°

      5x+17x+2=90°

      22x+2=90°

      22x=90-2

      22x=88

        22x/22=88/22

      x=88/22=<u>4</u>

m<A=5x=5*4=<u>20°</u>

m<B=17x+2=17*4+2=68+2=<u>70°</u>

         <u>Check</u>

A+B=90°

20+70=90°

<u>90°=90°</u>

32. A+B=180°

     x+11+x-15=180°

     2x-4=180°

     2x=180+4

     2x=184

     2x/2=184/2

     x=184/2

     x=<u>92</u>

m<A=x+11=92+11=<u>103°</u>

m<B=x-15=92-15=<u>77°</u>

     <u>Check</u>

A+B=180°

103+77=180°

<u>180°=180°</u>

6 0
2 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
2 years ago
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